Selected article for: "average number and infectious day"

Author: Lee, Hyunsun
Title: Stochastic and spatio-temporal analysis of the Middle East Respiratory Syndrome outbreak in South Korea, 2015
  • Document date: 2019_6_14
  • ID: 6cyhjt10_29
    Snippet: To calculate the reproductive rate for the MERS outbreak in South Korea, we use Equation (1) in a discrete form. The average number bðtÞ of new patients from an infectious patient per unit time (one day) and the survival function FðtÞ at time t are graphed in Fig. 8 . The calculated reproductive ratio based on these two functions is R ¼ 3:7949 which is considerably larger than 1 and this outbreak is classified as a major outbreak. For the pr.....
    Document: To calculate the reproductive rate for the MERS outbreak in South Korea, we use Equation (1) in a discrete form. The average number bðtÞ of new patients from an infectious patient per unit time (one day) and the survival function FðtÞ at time t are graphed in Fig. 8 . The calculated reproductive ratio based on these two functions is R ¼ 3:7949 which is considerably larger than 1 and this outbreak is classified as a major outbreak. For the probability of ultimate extinction that is the root of Equation (5), we define hðzÞ ¼ G 1 ðzÞ À z. The graph on the left in Fig. 9 shows hðzÞ and the probability of ultimate extinction for R > 1, i.e., the zero of the function hðzÞ less than 1, is located at z à ¼ 0:4996. The graph on the right shows the profile of the probability of ultimate extinction over the outbreak. The probability drops but immediately increases after the appearance of super-spreaders on Days 14e16, which indicates how important successful quarantine of super-spreaders is during an epidemic.

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